1.1x+(1.4x^2)+0.2=0

Solution for 1.1x+(1.4x^2)+0.2=0 equation:

1.1x+(1.4x^2)+0.2=0

We get rid of parentheses

1.4x^2+1.1x+0.2=0

a = 1.4; b = 1.1; c = +0.2;
Δ = b2-4ac
Δ = 1.12-4·1.4·0.2
Δ = 0.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.1)-\sqrt{0.09}}{2*1.4}=\frac{-1.1-\sqrt{0.09}}{2.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.1)+\sqrt{0.09}}{2*1.4}=\frac{-1.1+\sqrt{0.09}}{2.8}
$